First slide
Wave nature of matter
Question

An electron (mass m) with initial velocity ν=ν0i^+ν0j^  is in an electric field  E=E0k^. If  λ0 is initial de-Broglie wavelength of electron, its de-Broglie wavelength at time t is given by :

Difficult
Solution

  Initially momentum =p=m2V0=hλ0hm=2V0λ0     .........1 

Acceleration of electron = a=eE0mk^Using equation of kinematicsv=u+atv = v0i^+v0j^+eE0tmk^Magnitude of velocity =  v=v02+v02+eE0tm2 
  
  So,  wavelength = λ=hmv=hm2v02+e2E02t2m2
 λ=2 v0λ02v0×1+e2E022m2v02t2=λ01+e2E022m2v02t2

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