An electron (mass m) with an initial velocity v=voi^ is in an electric field E=Eoj^. If initial wavelength λ0=h/mvo then its de Broglie wavelength at time t is given by .

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λ0

λ01+e2E02t2m2v02

λ01+eEtmv0

answer is C.

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Detailed Solution

V=u+at=V0i^−emE0tj ^& V=V02+e2E02t2m2 λ=hmv=hmV021+e2E02t2mv2=hmv01+e2E02t2m2V02=λ01+e2E02t2m2V02

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