Q.
An electron of mass m with an initial velocity v→=v0i^v0>0 enters an electric field E→=-E→0i^ E0= constant >0 ) at t=0. If λ0 is its de-Broglie wavelength initially, then its de- Broglie wavelength at time t is
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a
λ01+eE0mv0t
b
λ01+eE0mv0t
c
λ0t
d
λ0
answer is A.
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Detailed Solution
Here, = λ01+eE0mv0tinitial; velocity v→=v0i^Force action on electron due to electric fieldF→=(-e)-E0i^=eE0i^ Acceleration produced in the electron, a→=F→m=eE0mi^Now, velocity of electron after time tv→t=v→+a→t=v0+eE0tmi^ or v→t=v0+eE0tm Now, λt=hmvt=hmv0+eE0tm=hmv01+eE0tmv0=λ01+eE0tmv0 ∵λ0=hmv0
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