An electron of mass 0.90 x 10-30 kg under the action of magnetic field moves in a circle of radius 2.0 cm at a speed of 3.0 x 106 m/sec. If a proton of mass 1.8 x 10-27 kg were to move in a circle of the same radius in the same magnetic field, then its speed will be
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a
3.0 x106 m,/sec
b
1 .5 x 103 m/sec
c
6x104 m/sec
d
cannot be estimated from the above data
answer is B.
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Detailed Solution
We know that r=mvqB∴ rpre=mpme×vpve ∵qp=qeGiven that rp = re∴ vp=ve×memp=3⋅0×1060⋅90×10−301⋅8×10−27=1⋅5×103m/s