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An electron of mass 0.90 x 10-30 kg under the action of a magnetic field moves in a circle of 2.0 cm radius at a speed of 3.0 x 106 ms-1. If a proton of mass 1.8 x 10-27 kg was to move in a circle of the same radius in the same magnetic field, then its speed will be

a
3.0x 106ms-1
b
1.5x103ms-1
c
6.0x 104ms-1
d
Cannot be estimated from the given data

detailed solution

Correct option is B

Bqv=mv2r or Bqr=mvFor electron as well as proton B is the same, r is the same and numerically charge  is same; therefore mv is constant.meve=mpvp or vp=mempve or   vp=0.90×10-301.8×10-273.0×106=1.5×103 m/s

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What is the value of B (in ×10-8 T ) that can be set up at the equator to permit a proton of speed 107 m/s to circulate around the earth? R=6.4×106 m,mP=1.67×10-27 kg


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