An electron is moving along +x direction with a velocity of 6×106 ms−1. It enters a region of uniform electric field of 300 V/cm pointing along +y direction. The magnitude and direction of the magnetic field set up in this region such that the electron keeps moving along the x-direction will be

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3×10−4 T,along –z direction

5×10−3 T,along –z direction

3×10−4 T,along +z direction

5×10−3 T,along +z direction

answer is D.

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Detailed Solution

For no deflection magnetic force should be along − y axis , so it can cancel electric force.Hence, magnetic field should be along +z axisFM=FE⇒qvB=qE⇒B=Ev=300×1026×106=5×10−3T along +Z

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