Questions
An electron moving with kinetic energy 6.6 x 10-14 J enters a magnetic field 4 X10-3 T at right angle to it, The radius of circular path will be nearest to
detailed solution
Correct option is B
evB=mv2/R or ebR=mvSquaring on both sides, we gete2B2R2=m2v2=2m12mv2=2m× K.E. ∴ R=(2m×K.E.)1/2eB=2×9⋅1×10−31×6⋅6×10−141/21.6×10−19×4×10−3= 54 cm, which is nearest to 50 cm.Talk to our academic expert!
Similar Questions
A charged beam consisting of electrons and positrons enter into a region of uniform magnetic field B perpendicular to field, with a speed v. The maximum separation between an electron and a positron will be (mass of electron = mass of positron = m)
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