First slide

Matter waves (DC Broglie waves)

Question

An electron and a photon have the same de Broglie wavelength. Then the kinetic energy of the electron is

Easy

A

equal to the kinetic energy of the photon
B

greater than the kinetic energy of the photon
C

zero
D

infinity

Solution

$λ = \frac{h}{mv} = \frac{h}{\sqrt{(2 mE)}} Thus, m_{e} E_{e} = m_{p} E_{p} \frac{E_{e}}{E_{p}} = \frac{m_{p}}{m_{e}} > 1 (∵ m_{p} > m_{e}) or E_{e} > E_{p}$

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