An electron placed at a distance of 0.5 m from a charge placed at origin, experiences a force of 9.6×10−16N along positive x-axis. The electric field at the position of electron is
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a
6×103NC−1along+ve x−axis
b
6×103NC−1along−ve x−axis
c
15.36×10−34NC−1along+ve x−axis
d
15.36×10−34NC−1along−ve x−axis
answer is B.
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Detailed Solution
E=Fq=9.6×10-161.6×10-19=6×103 N/Con -ive charge F and E are in opposite direction