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Q.

An electron placed at a distance of 0.5 m from a charge placed at origin, experiences a force of 9.6×10−16N along positive x-axis. The electric field at the position of electron is

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a

6×103NC−1along+ve x−axis

b

6×103NC−1along−ve x−axis

c

15.36×10−34NC−1along+ve x−axis

d

15.36×10−34NC−1along−ve x−axis

answer is B.

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Detailed Solution

E=Fq=9.6×10-161.6×10-19=6×103 N/Con -ive charge F and E are in opposite direction
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