An electron is projected at an angle θ with a uniform magnetic field. If the pitch of the helical path is equal to its radius, then the angle of projection is
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a
tan-1π
b
tan-12π
c
cot-1π
d
cot-12π
answer is B.
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Detailed Solution
r=mvsinθqB, Pitch: p=vcosθT=vcosθ2πmqB Now, p=r, solve to get θ=tan-12π