An electron is released from rest in an uniform electric field of 576 N/C. Then,
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a
it does not experience any force
b
its initial acceleration is 1.01×1014m/s2
c
its acceleration increases as it moves along the field
d
acceleration is directed opposite to field
answer is B.
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Detailed Solution
Acceleration of a charge q, when released from rest in a field of intensity E is a=Fm=qEm∴ For electron, a=eEm=1.6×10−19×5769.1×10−31=1.01×1014m/s2Acceleration is constant.Also, electron is accelerated opposite to field.