Q.

An electron is released from rest in an uniform electric field of 576 N/C. Then,

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a

it does not experience any force

b

its initial acceleration is 1.01×1014m/s2

c

its acceleration increases as it moves along the field

d

acceleration is directed opposite to field

answer is B.

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Detailed Solution

Acceleration of a charge q, when released from rest in a field of intensity E is                                 a=Fm=qEm∴  For electron, a=eEm=1.6×10−19×5769.1×10−31=1.01×1014m/s2Acceleration is constant.Also, electron is accelerated opposite to field.
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