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Q.

An electron is released with a velocity of 5 × 106 ms-1 in an electric field of 103 N C-1 which has been applied so as to oppose its motion. How much time could it take before it is brought to rest?

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a

2.8×10−8s

b

1.8×10−8s

c

6.4×10−8s

d

4.2×10−8s

answer is A.

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Detailed Solution

Since electric field is applied so as to oppose the motion of electron,a=−eEmretardation=−1.6×10−19×1039.1×10−31=−1.758×1014ms−2Now,   u=5×106ms−1,   v=0Using  the  relation:  v2−u2=2as,  we  gets=7.11×10−2mUsing  the   relation  :  v=u+at,  we  gett=2.844×10−8s
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An electron is released with a velocity of 5 × 106 ms-1 in an electric field of 103 N C-1 which has been applied so as to oppose its motion. How much time could it take before it is brought to rest?