Q.
An electron is released with a velocity of 5 × 106 ms-1 in an electric field of 103 N C-1 which has been applied so as to oppose its motion. How much time could it take before it is brought to rest?
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a
2.8×10−8s
b
1.8×10−8s
c
6.4×10−8s
d
4.2×10−8s
answer is A.
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Detailed Solution
Since electric field is applied so as to oppose the motion of electron,a=−eEmretardation=−1.6×10−19×1039.1×10−31=−1.758×1014ms−2Now, u=5×106ms−1, v=0Using the relation: v2−u2=2as, we gets=7.11×10−2mUsing the relation : v=u+at, we gett=2.844×10−8s
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