An electron revolves round the nucleus of a hydrogen like element with a velocity 3/2 times that of the electron in the first orbit of H atom. If the radius ot that orbit is 8/3 times that of the first orbit of H atom then the wrong statement is
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a
atomic no of element is 6
b
the number of revolving orbit is 4
c
energy of the electron in that orbit is 15.3 eV
d
the angular momentum of the electron is 2hπ
answer is C.
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Detailed Solution
velocity of the electron in any orbit of an atom is proportional to Zn radius is proportional to n2ZvvH= 32 =ZZH nHn ------1 rrH=83=n2nH2ZHZ--------2 multiplying 1 and 2 4=nnH=n substituting n=4 we get z=6 angular momentum 4h2π=2hπ energy 13.6Z2n2=30.6