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Q.

An electron revolves round the nucleus of a hydrogen like element with a velocity 3/2 times that of the electron in the first orbit of H atom. If the radius ot that orbit is 8/3 times that of the first orbit of H atom  then  the wrong statement is

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a

atomic no of element is 6

b

the number of revolving orbit is 4

c

energy of the electron in that orbit is 15.3 eV

d

the angular momentum of the electron is 2hπ

answer is C.

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Detailed Solution

velocity of the electron in any orbit of an atom is proportional to Zn radius is proportional to n2ZvvH= 32 =ZZH nHn   ------1  rrH=83=n2nH2ZHZ--------2  multiplying 1 and 2   4=nnH=n     substituting n=4 we get z=6  angular momentum 4h2π=2hπ   energy  13.6Z2n2=30.6
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