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An electron is revolving round a proton, producing a magnetic field of 16 Wb/m2 in a circular orbit of radius 1Ao.  Its angular velocity will be

a
1017 rad/s
b
1/2  π × 1012 rad/s
c
2  π × 1012 rad/s
d
4  π × 1012 rad/s

detailed solution

Correct option is A

Magnetic field due to revolution of electron,B  =  μ04π . 2πir  =  μ04π . 2π . eω2πr = 10−7 ×  eωr⇒  16  =  10−7  ×  1.6 × 10−19 ω 1  ×10−10  ⇒ ω = 1017  rad/s

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