Questions
An electron is revolving round a proton, producing a magnetic field of 16 Wb/m2 in a circular orbit of radius . Its angular velocity will be
detailed solution
Correct option is A
Magnetic field due to revolution of electron,B = μ04π . 2πir = μ04π . 2π . eω2πr = 10−7 × eωr⇒ 16 = 10−7 × 1.6 × 10−19 ω 1 ×10−10 ⇒ ω = 1017 rad/sTalk to our academic expert!
Similar Questions
An electron moves in a circular orbit with a uniform speed v. It produces a magnetic field B at the centre of the circle. The radius of the circle is proportional to
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests