First slide

Force on a charged particle moving in a magnetic field

Question

An electron is shot in steady electric and magnetic fields such that its velocity v, electric field E and magnetic field B are mutually perpendicular. The magnitude of E is 1volt/ cm and that of B is 2 tesla. Now it so happens that the Lorentz (magnetic) force cancels the electrostatic force on the electron, then the velocity of electron is

Easy

A

50 m/s
B

2 m/s
C

0 . 5 cm/s
D

200 m/s

Solution

$\begin{aligned} v = \frac{E}{B} = \frac{1 volt / cm}{2 tesla} \\ = \frac{100 V / m}{2 tesla} = 50 m / s \end{aligned}$

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