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An electron with speed V and a photon with speed C have the same de Broglie wave length. If the energy and momentum of electron are Ee and Pe and that of photon are Ep and Pp respectively, Then correct statement is _____

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a

EeEp=2cV

b

EeEp=V2c

c

PePp=2cV

d

PePp=V2c

answer is B.

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Detailed Solution

EeEp=12 mV2hν=12 V × mVh× hhν = V2×1λe×1cλpSince λe = λpEeEp= V2cAlso, Since λe = λpWe can writehPe = hPp⇒ Pe = Pp

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