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Q.

An electron-beam passes through a magnetic field B of 2x10-3 Weber/m2 and an electric field E of 3.4x104 volt / met re acting simultaneously. If the path of the electron remains undeviated, the speed of the electron will be

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a

1.7 x 107 m/s

b

4.7 x 107 m/s

c

7.1 x 107 m/s

d

3.0 x 108  m/s

answer is A.

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Detailed Solution

Be v = e EV=EB=3⋅14×1042×10−3=1⋅7×107m/s
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