An $$electron-beam$$ passes through a magnetic field B of $$2x10-3$$ $$Weber/m2$$ and an electric field E of $$3.4x104$$ volt $$/$$ met re acting simultaneously. If the path of the electron remains undeviated, the speed of the electron will be

Correct option is 11.7 x 107 m/s

Questions

An electron-beam passes through a magnetic field B of 2x10^-3 Weber/m² and an electric field E of 3.4x10⁴ volt / met re acting simultaneously. If the path of the electron remains undeviated, the speed of the electron will be

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detailed solution

Correct option is A

Be v = e EV=EB=3⋅14×1042×10−3=1⋅7×107m/s

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An electron-beam passes through a magnetic field B of 2x10-3 Weber/m2 and an electric field E of 3.4x104 volt / met re acting simultaneously. If the path of the electron remains undeviated, the speed of the electron will be

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An electron-beam passes through a magnetic field B of 2x10^-3 Weber/m² and an electric field E of 3.4x10⁴ volt / met re acting simultaneously. If the path of the electron remains undeviated, the speed of the electron will be