Electrons emerge from an electron accelerator as a beam having a circular cross-section of diameter 3 mm. The beam current is 6 μA and electrons are travelling so fast that their speed can be taken as c = 3 x 108 m/sec with an insignificant error. Electron density in the beam is :

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2.82 x 1011 m-3

1.77 x 1010 m-3

1.54 x 109 m-3

1.28 x 109 m-3

answer is B.

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Detailed Solution

I=neAvd ⇒n=IeAvd=6 x 10-61.6 x 10-19π1.5 x 10-323 x 108 =1.77 x 1010 m-3

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