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Electrons from n=2 to n=1 in Hydrogen atom is made to fall on a metal surface with work function 1.2ev. The maximum velocity of photo electrons emitted is nearly equal to

a
6 ×105 m/s
b
3 ×105 m/s
c
2 ×105 m/s
d
18 ×105 m/s

detailed solution

Correct option is D

KEmax=E-Wo ∴12mVmax2=13.6z21n12−1n22−Wo ∴12×9×10−31Vmax2=13.6(1)2112−122−1.2eV ∴12×9×10−31Vmax2=[10.2−1.2]eV ∴12×9×10−31Vmax2=9×1.6×10−19 ∴Vmax=18×105ms−1

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