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Q.

The electrons in a particle beam each have a kinetic energy of 1.6×10−17J.   What are the magnitude and direction of the electric field that stops these electrons in a distance of 10.0 cm

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a

103 v/m  in the direction of velocity of electrons

b

103 v/m  positive direction of velocity of electrons

c

103 v/m  perpendicular to velocity of electrons

d

106 v/m  perpendicular to velocity of electrons

answer is A.

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Detailed Solution

K.Ef-K.Ei=F×S0-1.6×10-17=-E×1.6×10-19×0.1E=103vm  in  the  direction  of  velocity
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