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Q.

Electrons with de-Broglie wavelength λ  falls on the target in an x-ray tube. The cut- off wavelength of the emitted X-ray is

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a

2mcλ2h

b

2hmc

c

2m2c2λ2h2

d

λ

answer is A.

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Detailed Solution

P=hλ                     kE=P22m=h22mλ2=hcλ0
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