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Electrons with de-Broglie wavelength λ  falls on the target in an x-ray tube. The cut- off wavelength of the emitted X-ray is 

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a
2mcλ2h
b
2hmc
c
2m2c2λ2h2
d
λ

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detailed solution

Correct option is A

P=hλ                     kE=P22m=h22mλ2=hcλ0

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