Q.
Electrons with de-Broglie wavelength λ falls on the target in an x-ray tube. The cut- off wavelength of the emitted X-ray is
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a
2mcλ2h
b
2hmc
c
2m2c2λ2h2
d
λ
answer is A.
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Detailed Solution
P=hλ kE=P22m=h22mλ2=hcλ0
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