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Q.

The electrostatic energy of Z protons uniformly distributed throughout a spherical nucleus of radius R is given by  E=35ZZ−1e24πε0R The measured masses of the neutron,    11H,  715N  and  815O  are 1.008665 u, 1.007825 u, 15.000109 u and 15.003065 u, respectively. Given that the radii of both the  715N  and   815O nuclei are same,  1u=931.5 MeV/c2 (c is the speed of light) and e2/4πε0=1.44 MeV fm. Assuming that the difference between the binding energies of   715N and  815O  is purely due to the electrostatic energy, the radius of either of the nuclei is  1fm=10−15

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a

2.85 fm

b

3.03 fm

c

3.42 fm

d

3.80 fm

answer is C.

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Detailed Solution

Binding energy of nitogen atom=8×1.008665+7×1.007825−15.000109931.5​Binding energy of oxygen atom=7×1.008665+8×1.007825−15.003065931.5​∴Difference in BE=0.0037960×931.5=3.54 MeVNow, ​Difference in electrostatic energy=EO−EN=358×7R−7×6R1.44MeV fm=12.096RMeV fmBoth differences are equal, ​12.096RMeV fm=3.54 MeV​⇒R=3.42fm
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