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Q.

An elevator cable is to have a maximum stress of 7 x 107 Nm-2 to allow for appropriate safety  factors. Its maximum upward acceleration is 1.5 ms-2. If the cable has to support the total weight of 2000 kg of a loaded elevator, the area of cross-section of the cable should be

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a

3.23 cm2

b

2.38 cm2

c

0.32 cm2

d

8.23 cm2

answer is A.

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Detailed Solution

Tension,  Tmax=m(g+a)=(2000)(9.8+1.5)=22600N∵ Maximum stress  =Tmax Area ∴    Area =Tmax Maximum stress =226007×107=3.23×10−4m2=3.23cm2
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