Q.

An elevator car, whose floor to ceiling distance is equal to 2.7 m, starts ascending with constant acceleration of 1.2 ms-2.2 sec after the start, a bolt begins fall from the ceiling of the car. The free fall time of the bolt is

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a

0.54 s

b

6 s

c

0.7 s

d

1 s

answer is C.

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Detailed Solution

given height =h=2.7m acceleration of lift upward=a=1.2m/s2;  acceleration due to gravity=9.8m/s2  anet =g+a  u=0  time taken by bolt to reach floor=t=2h(g+a) t=2×2.7(9.8+1.2)=5.411=0.49=0.7sec
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