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Q.

An elevator carrying a charge of 0.5C is moving down with a velocity of 5 x 103 ms-1. The elevator is 4 m  from the bottom and 3 m horizontally away from P as shown in figure. What magnetic field (in μT) does it produce at point P?

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answer is 6.

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Detailed Solution

According to Biot-Savart law,B=μ04πqvr2sinθ=10-7×0.5×5×1035235=6μT
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