An elevator and its load have a total mass of 800 kg. The elevator is originally moving downwards at 10 ms-1 it slows down to stop with constant acceleration in a distance of 25 m. Find the tension T in the supporting cable while the elevator is being brought to rest. (Take g = 10 ms-2)

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8000 N

1600 N

9600 N

6400 N

answer is C.

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Detailed Solution

When the elevator is going down with a retardation T = mg+a where a is here u22s=1002×25=2 m/s2 T=80010+2=9600 N

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