An elevator and its load have a total mass of 800kg. The elevator is originally moving downwards at 10ms-1, it slows down to stop with constant acceleration in a distance of 25m. Find the tension T in the supporting cable while the elevator is being brought to rest. (Take g = 10ms-2)

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8000 N

1600 N

9600 N

6400 N

answer is C.

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Detailed Solution

as it is going down with retardation then acceleration of the elevator is vertically upward.then T= M(g+a)here a=u22s=1002×25=2 m/s2T= 800(10+2)=9600 N

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