First slide

Different types of Forces

Question

An elevator and its load have a total mass of 800kg. The elevator is originally moving downwards at 10 $m s^{- 1}$ , it slows down to stop with constant acceleration in a distance of 25m. Find the tension T in the supporting cable while the elevator is being brought to rest. (Take g = 10 $m s^{- 2}$ )

Easy

A

8000 N
B

1600 N
C

9600 N
D

6400 N

Solution

as it is going down with retardation then acceleration of the elevator is vertically upward.
then T= M(g+a)
here $a = \frac{u^{2}}{2 s} = \frac{100}{2 \times 25} = 2 m / s^{2}$
T= 800(10+2)=9600 N

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