Q.

An elevator without a ceiling is ascending up with an acceleration of 5 ms-2 A boy on the elevator shoots a ball in vertical upward direction from a height of 2 m above the floor of elevator. At this instant the elevator is moving up with a velocity of 10 ms-1 and floor of the elevator is at a height of 50 mfrom the ground. The initial speed of the ball is 15 ms-1 with respect to the elevator. Consider the duration for which the ball strikes the floor of elevator in answering following questions. g=10ms-2The time in which the ball strikes the floor of elevator is given byThe maximum height reached by ball, as measured from the ground would beDisplacement of ball with respect to ground during its flight would beThe maximum separation between the floor of elevator and the ball during its flight would be

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a

2.13 s

b

2.0 s

c

1.0 s

d

3.12 s

e

73.65 m

f

116.25 m

g

82.56 m

h

63.25 m

i

16.25 m

j

8.76 m

k

20.24 m

l

30.56 m

m

12 m

n

9.5 m

o

15 m

p

7.5 m

answer is , , , .

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Detailed Solution

Velocity of ball with respect to elevator is 15 m/s (up) and elevator has a velocity of 10 m/s (up). Therefore, absolute velocity of ball is 25 m/s (upwards). Ball strikes the floor of elevator if,S1=S2+2 ∴  10t+2.5t2=25t-5t2+2Solving this equation we get,t=2.13 sIf the ball does not collide, then it will reach its maximum height in time,t0=ug=2510=2.5 sSince, t
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