The elongation in a metallic rod hinged at one end and rotating in a horizontal plane becomes four times of the initial value. The angular velocity of rotation becomes
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a
two times the initial value
b
half of initial value
c
one third of initial value
d
four times the initial value
answer is A.
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Detailed Solution
-∫T0∆T = ∫0lmldxω2 x ⇒ T = mlω2x22⇒ Y =FlA∆lδl = FlAYδl = mlω2x22dxAY∆l=∫δl = mω2l3 6AYl ∆l = ρω2l36Y∆ l ∝ ω2For elongation to become 4 times the final angular speed must beω2 = 2ω1
The elongation in a metallic rod hinged at one end and rotating in a horizontal plane becomes four times of the initial value. The angular velocity of rotation becomes