First slide
Simple hormonic motion
Question

The elongation of a spring of length ‘L’ and of negligible mass due to a force is ‘x’. The spring is cut into two pieces of length in ratio 1 : n. The ratio of the respective spring constants is

Easy
Solution

\large k\, \propto \,\frac{1}{l}

\large \therefore \,\frac{{{k_1}}}{{{k_2}}}\, = \,\frac{{{l_2}}}{{{l_1}}}\, = \,\frac{n}{1}\, = \,n

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