The e.m.f. of the driver cell of a potentiometer is 2V and its internal resistance is negligible. The length of the potentiometer wire is 100 cm and resistance is 5 ohms. How much resistance is to be connected in series with the potentiometer wire to have a potential gradient of 0.05 mVcm-1 ?

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1990 ohms

2000 ohms

1995 ohms

1920 ohms

answer is C.

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Detailed Solution

potential gradient =iRPL=E RPLRs+RP=0.05 x10-310-2 V/m 2 x 51Rs+5= 5 x 10-3 Rs=1995

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