The e.m.f. of the driver cell of a potentiometer is 2V and its internal resistance is negligible. The length of the potentiometer wire is 100 cm and resistance is 5 ohms. How much resistance is to be connected in series with the potentiometer wire to have a potential gradient of 0.05 mVcm-1 ?
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
1990 ohms
b
2000 ohms
c
1995 ohms
d
1920 ohms
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
potential gradient =iRPL=E RPLRs+RP=0.05 x10-310-2 V/m 2 x 51Rs+5= 5 x 10-3 Rs=1995