The emf and internal resistance of the battery shown in figure are 4.3 V and 1Ω respectively. The external resistance R is 50Ω . The resistance of the voltmeter and ammeter are 200Ω and 2Ω respectively. Find the readings of the two meters.

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0.1 A, 2 V

0.1 A, 4 V

0.4 A, 1 V

04.A, 4 V

answer is B.

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Detailed Solution

First of all the draw the equivalent circuit diagram, current flowing through circuit =4.350||200+2+1=0.1AVoltmeter reading = 4.3 – 0.1 x 3 = 4 V

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