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An emf of 96.0 mV is induced in the windings of a coil when the current in a nearby coil is increasing at the rate of 1 .20 A/s The mutual inductance of the two coils is

a
40 mH
b
20 mH
c
10 mH
d
80 mH

detailed solution

Correct option is D

we use equation, ε2=−Mdi1dtfrom which we obtain the mutual inductance:M=ε2di1/dt=0.0960V1.20A/s=0.080H=80mH

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