An e.m.f. of 15 v is applied in a circuit containing 5 H inductance and 10 Ω resistance. The ratio of the currents at time t=∞ and at t = 1 s is
e1/2e1/2-1
e2e2-1
1-e-1
e-1
i=i01-e-Rt/L
i0=ER (Steady current) when t=∞
i∞=ER1-e-∞=510=1.5
i1=1.51-e-R/L=1.51-e-2
⇒i∞i1=11-e-2=e2e2-1