First slide

Inductance

Question

An e.m.f. of 5 V is produced by a self-inductance, when the current changes at a steady rate from 3 A to 2 A in 1 millisecond. The value of self-inductance is

Easy

A

Zero
B

5 H
C

5000 H
D

5 mH

Solution

$L = - \frac{e}{di / dt} = - \frac{5}{(2 - 3) / 10^{- 3}} = \frac{5}{1} \times 10^{- 3} = 5 mH$

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