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An e.m.f. of 5 V is produced by a self-inductance, when the current changes at a steady rate from 3 A to 2 A in 1 millisecond. The value of self-inductance is

a
Zero
b
5 H
c
5000 H
d
5 mH

detailed solution

Correct option is D

L=-edi/dt=-5(2-3)/10-3=51×10-3=5mH

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