First slide

Faraday's law of Electromagnetic induction

Question

An e.m.f. of 2 volt is produced in a coil when the current changes at a steady rate from 3 to 2 amperes in 1 milli-second. The value of self-inductance is

Easy

A

zero
B

2 mH
C

2 H
D

200 mH

Solution

$e = L \frac{di}{dt} or 2 = L [\frac{(3 - 2)}{10^{- 3}}] ∴ L = \frac{2 \times 10^{- 3}}{1} = 2 mH$

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