An e.m.f. of 12 volts is induced in a given coil when the current in it changes at the rate of 48 amperes per minute. The self inductance of the coil is

Two different coils have self-inductance  ${\mathrm{L}}_1=8$mH, ${\mathrm{L}}_2=2\mathrm{mH}$ . The current in one coil is increased at a constant rate. The current in the second coil is also increased at the same rate. At a certain instant of time, the power given to the two coils is the same. At that time the current, the induced voltage and the energy stored in the first coil are ${\mathrm{i}}_1,{\mathrm{V}}_1$ and ${\mathrm{W}}_1$ respectively. Corresponding values for the second coil at the same instant are ${\mathrm{i}}_2,{\mathrm{V}}_2$  and ${\mathrm{W}}_2$ respectively. Then