The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment, the displacement of the wire is and energy is E1, and in another experiment its displacement is and energy is E2. Then
Energy (E) (Amplitude)2 (Frequency)2
Amplitude is same in both the cases, but frequency 2 in the second case is two times the frequency () in the first case. Hence .