The ends of a stretched wire of length tr are fixed at x =o and x = l. In one experiment, the displacement of the wire is y₁ =A sin ($\pi$x/ L) sin $\omega$t and energy is E₁ and in another experiment its displacement is y₂ =A sin,(2$\pi$ x L) sin 2 $\omega$t and energy is E₂. Then

• A

  E₂ = E₁

• B

  E₂ = 2E₁

• C

  ${\mathrm{E}}_2=4{\mathrm{E}}_1$

• D

  ${\mathrm{E}}_2=16{\mathrm{E}}_1$