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Questions  

The ends of a stretched wire of length tr are fixed at x =o and x = l. In one experiment, the displacement of the wire is y1 =A sin (πx/ L) sin ωt and energy is E1 and in another experiment its displacement is y2 =A sin,(2π x L) sin 2 ωt and energy is E2. Then

a
E2 = E1
b
E2 = 2E1
c
E2=4E1
d
E2=16E1

detailed solution

Correct option is C

We know that E ∝ω2

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