The ends of two identical strings are tied to two rigid walls and same tension is maintained in them. The strings are oscillating in their fundamental made with frequency 100 Hz. If the tension in one of them is increased by 6%, then frequency of beats is
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a
3
b
2
c
4
d
5
answer is A.
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Detailed Solution
Fundamental frequency f=12lTμWhen tension in one string is increased by 6%, f1=12lT1μ∴ f1f=T1T=1.06TT=1+6100=1+126100∴ f1−ff=126100⇒f1−f=62×100×100=3