The ends of two rods of different materials having thermal conductivities, radii of cross-section and Iengths in the ratio 1 : 2, arc maintained at the same temperature difference. If the rate of flow of heat in the larger rod is 4 cal/s, then in shorter rod in cal/s will be
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a
1
b
2
c
8
d
16
answer is A.
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Detailed Solution
We know that (ΔQ/Δt)=KA(ΔT/d)=Kπr2(ΔT/d)∴ (ΔQ/Δt)1(ΔQ/Δt)2=K1r12d1×d2K2r22 =12×21×122=14 or (ΔQ/Δt)1/4=1/4 or (ΔQ/Δt)1=1