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Q.

The ends of two rods P and Q are kept at temperatures θ1oC and θ2oC .Rod P has radius r, length l and coefficient of thermal conductivity k. Rod Q has radius r/2 length l/2 and thermal conductivity 2k. Lateral surfaces of the rods are covered by insulating material. Rate of conduction of heat conduction through the rods P and Q are QP and QQ respectively, then

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a

QP=QQ

b

QP>QQ

c

QP

d

Information is not sufficient to find the relation between QP and QQ.

answer is A.

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Detailed Solution

Q = Rate of heat conduction =θ1-θ2RWhere R = Thermal resistance =lkA=lk.πr2∴QPQQ=RQRP=lQlP.rPrQ2.kPkQ=12.22.12=1⇒QP=QQ
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