Q.

Energy of all molecules of a monatomic gas having a volume V and pressure P is 3/2 PV. The total translational kinetic energy of all molecules of a diatomic gas at the same volume and pressure is

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a

1/2 PV

b

3/2 PV

c

5/2 PV

d

3 PV

answer is B.

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Detailed Solution

Energy of 1 mol of gas =f2RT=f2PVwhere f = degree of freedomMonatomic or diatomic gases possess equal degree of freedom for translational motion and that is equal to 3, i.e., f = 3∴ E=32PV
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