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As energy associated with changes with its wavelength, often the reciprocal of the wavelength 1/λ. is used to describe energy associated with that wavelength. Then, mark the correct equivalence.

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a

1eV=5092.6cm−1 and 1cm−1=1.2398×10−4eV

b

1eV=1239.8cm−1 and 1cm−1=8068×10−7eV

c

1eV=8068.8cm−1 and 1cm−1=6.65×10−19eV

d

1eV=8065×10−19cm−1 and 1cm−1=1.2398×10−4eV

answer is C.

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Detailed Solution

As, hf=E⇒ hcλ=E ⇒ 1λ=Ehc Now, hc≈1240eV−nm⇒ hc≈1240×10−7eV−cm So, 1λ=1eV1240×10−7eV−cm( when E=1eV)=8065.8cm−1So, a wave length reciprocal 1λ of 8065.8 cm-1 corresponds to an energy of 1 eV.

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As energy associated with changes with its wavelength, often the reciprocal of the wavelength 1/λ. is used to describe energy associated with that wavelength. Then, mark the correct equivalence.