Energy is being emitted from the surface a black body at $$127$$∘C temperature at $$1$$×$$106Js-1m-2$$, temperature of the black body at which the rate of emission is $$16$$×$$106Js-1m-2$$ will be

Question

Energy is being emitted from the surface a black body at  $$127$$∘C temperature at $$1$$×$$106Js-1m-2$$, temperature of the black body at which the rate of emission is $$16$$×$$106Js-1m-2$$ will be

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given temperature of black body is $$T1=127+273=400K$$      $$T2=$$?  energy emitted by black body is $$E1=1$$×$$106$$ $$Js-1m-2$$       $$E2=16$$×$$106$$ $$Js-1m-2$$  from stefan's law,   E $$=$$σ $$T4$$ ⇒E α $$T4$$ ⇒$$E1E2=T1T24$$ ⇒$$E1E2=400T24$$ ⇒$$(E1E2)14=400T$$   ⇒$$10616$$×$$10614=400T$$⇒  $$12$$ $$=$$   $$400T$$ ⇒   T $$=$$   $$800$$  K $$=$$   $$800$$  $$-$$  $$273$$ $$=$$   $$527$$  °  C

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