First slide

Bohr's atom model

Question

The energy of an electron in an excited hydrogen atom is -3.4 eV. Then, according to Bohr's Theory the angular momentum of this electron, in J s, is

Moderate

A

$2.11 \times 10^{- 34}$
B

$3 \times 10^{- 34}$
C

$1.055 \times 10^{- 34}$
D

$0.5 \times 10^{- 34}$

Solution

$E_{n} = - 3.4 eV, E_{n} \propto \frac{1}{n^{2}} E_{1} = - 13.6 eV Clearly, n = 2 Angular momentum = \frac{nh}{2 π} = \frac{2 h}{2 π} = \frac{h}{π} = 2.11 \times 10^{- 34} Js$

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