First slide

Bohr's atom model

Question

An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons from a neutral helium atom is

Easy

A

79.0
B

51.8
C

49.2
D

38.2

Solution

After the removal of first electron remaining atom will be hydrogen like atom.
So energy required to remove second electron from the atom $E = 13.6 \frac{Z^{2}}{n^{2}} = 13.6 \times \frac{2^{2}}{1^{2}} = 54.4 eV$
$∴ Total energy required = 24.6 + 54.4 = 79 eV$

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