First slide

Bohr Model of the Hydrogen atom.

Question

The energy of the highest energy photon of Balmer series of Hydrogen spectrum is close to

Easy

Solution

$E = 13 .6 [\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}]$
For highest energy in Balmer series $n_{1} = 2$ and $n_{2} = \infty$
$\frac{13.6}{4} = 3.4 e V$

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