Q.
The energy of a hydrogen atom in its ground state is -13.6 eV. The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is
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a
-2.72 eV
b
-0.85 eV
c
-0.54 eV
d
-3.4 eV
answer is D.
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Detailed Solution
En=-13.6n2=-13.64=-3.4eV
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