Q.

The energy of a hydrogen atom in its ground state is -13.6 eV. The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is

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a

-2.72 eV

b

-0.85 eV

c

-0.54 eV

d

-3.4 eV

answer is D.

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Detailed Solution

En=-13.6n2=-13.64=-3.4eV
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