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Q.

The energy liberated on complete fission of 1 kg of  92U235  is (Assume 200 MeV energy is liberated on fission of 1 nucleus)

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a

8.2×1010J

b

8.2×109J

c

8.2×1013J

d

8.2×1016J

answer is C.

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Detailed Solution

Mass of a uranium nucleus=92×1.6725×10−27+143×1.6747×10−27=393.35×10−27kgNumber of nuclei in the given mass=1393.35×10−27=2.542×1024 Energy released =200×2.542×1024MeV=5.08×1026MeV=8.135×1013J=8.2×1013J
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